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Mariana [72]
3 years ago
9

In the diagram below, AB and BC are tangent to O. What is the measure of angle B?APEX

Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

Answer:

C. 54^o

Step-by-step explanation:

We have been given a circle O. AB and AC are tangent of our given circle.

Since angle B is formed by tangents outside our given circle, so we will use tangent-tangent theorem.

Tangent-Tangent theorem states that when an angle is formed outside the circle by two tangents, then the measure of angle equals half the difference of its corresponding arcs.

m\angle B=\frac{\text{Major arc - Minor arc}}{2}

m\angle B=\frac{234^o-126^o}{2}

m\angle B=\frac{108^o}{2}

m\angle B=54^o

Therefore, the measure of angle B is 54 degrees and option C is the correct choice.

Whitepunk [10]3 years ago
4 0

option C <B = 54° ( answer is attached )

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6. A prism has bases that are equilateral triangles with sides lengths of 10 inches and a length of 30 inches.
eimsori [14]

Answer:

The volume of the prism is 1,299\ in^{3}

Step-by-step explanation:

we know that

The volume of the prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

L=30\ in

<em>Find the area of the base B</em>

The area of a equilateral triangle is equal to

B=\frac{1}{2}(10)^{2} sin(60\°)

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substitute

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8 0
3 years ago
Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

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Oksana_A [137]

Answer:

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Step-by-step explanation:

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