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katrin2010 [14]
2 years ago
6

find the value of each variable in the circle to the right. the dot represents the center of the circle.

Mathematics
1 answer:
gladu [14]2 years ago
3 0

We have been given an image of a circle. We are asked to find the value of each variable.

We can see that angle b corresponds to diameter of circle. We know that the measure of an angle that is inscribed to the diameter of a circle is 90 degrees . Therefore, the value of b will be 90.

we can see that angle is an inscribed angle of arc 99 degrees. We know that measure of an inscribed angle is half the measure of inscribed arc.

a=\frac{1}{2}\cdot 99

a=49.5

Therefore, the value of a is 49.5 units.

We know that measure of all angles of a triangle is 180 degrees. The measure of 3rd angle will be half the measure of c, so we can set an equation as:

a+b+\frac{1}{2}c=180

49.5+90+\frac{1}{2}c=180

139.5+\frac{1}{2}c=180

139.5-139.5+\frac{1}{2}c=180-139.5

\frac{1}{2}c=40.5

\frac{1}{2}c\cdot 2=40.5\cdot 2

c=81

Therefore, the value of c is 81.

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katrin2010 [14]

Answer: H_0:\mu=120

H_A:\mu\neq120

Step-by-step explanation:

Let \mu denotes the average braking distance for a population of small car.

Given : It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet.

i.e. \mu=120

Objective of test : Whether the statement made in the advertisement is false

i.e.  \mu\neq120

Since '=' signs is contained by Null hypothesis and alternative hypothesis is against it.

So the null and the alternative hypotheses for the test will be:

H_0:\mu=120

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Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

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initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

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The average velocity of the ball in ft/s is given as;

V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s

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answer:

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