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3 years ago

the product of 2 consecutive odd integers is equal to 27 plus six times the sum of the integers. what is the larger integer

1 answer:

8 0

2 consecutive odd integers : x and x + 2

x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0

x + 3 = 0
x = -3 (extraneous solution)

x - 13 = 0
x = 13

x + 2 = 15

so ur 2 integers are 13 and 15, with 15 being the largest

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Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

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