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erica [24]
3 years ago
14

the product of 2 consecutive odd integers is equal to 27 plus six times the sum of the integers. what is the larger integer

Mathematics
1 answer:
olganol [36]3 years ago
8 0
2 consecutive odd integers : x and x + 2

x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0

x + 3 = 0
x = -3 (extraneous solution)

x - 13 = 0
x = 13

x + 2 = 15 

so ur 2 integers are 13 and 15, with 15 being the largest
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-3/20

Step-by-step explanation:

Let other number = x

∴ -9/20 + x = -3/5

∴ x = -3/5 + 9/20

∴ x = -3/20

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Samantha and Matt are each saving for new bikes. So far, Samantha has saved $15 and can earn $2 per hour for babysitting. Matt h
Sophie [7]

Answer:

  • 6 hours

Step-by-step explanation:

<u>We know that:</u>

  • Samantha = 15 + 2x
  • Matt = 3 + 4x
  • Samantha = Matt
  • [x = Number of hours]

<u>Solution:</u>

  • 15 + 2x = 3 + 4x
  • => 15 - 3 = -2x + 4x
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Hence, after 6 hours of work, Samantha and Matt will have the same amount.

7 0
2 years ago
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3 years ago
Victor has a credit card with an apr of 13.66%, compounded monthly. he currently owes a balance of $1,349.34. assuming that vict
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Answer:

$1545.65.

Step-by-step explanation:

We have been given that Victor has a credit card with an APR of 13.66%, compounded monthly. He currently owes a balance of $1,349.34.

To solve our given problem we will use compound interest formula.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

Let us convert our given interest rate in decimal form. 13.66=\frac{13.66}{100}=0.1366

Upon substituting our given values in compound interest formula we will get,

A=1,349.34(1+\frac{0.1366}{12})^{12*1

A=1,349.34(1+0.011383333)^{12

A=1.349.34(1.011383333)

A=1,349.34*1.145485275522

A=1,545.64910167397 ≈ $1545.65

Therefore, Victor will owe an amount of $1545.65 after one year.

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2 years ago
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