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nirvana33 [79]
3 years ago
12

What is the solution set for --4w – 7 > w +3?

Mathematics
2 answers:
kirill [66]3 years ago
5 0

Answer:   w ≤  -2

Step-by-step explanation:

maksim [4K]3 years ago
3 0

Answer:

c: w < 2

Step-by-step explanation:

first move the left w to the left side of the equation which becomes -5w -7 > 3

and then move -7 to the right side of the equation. -5w> -10 and then divide -10 by -5 but since your dividing by a negative number u flip the sign and it becomes w < 2

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5

Step-by-step explanation:

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3 years ago
The wheels on Darlene's car have on 11-inch radius. If the wheels are rotating at a rate of 378 rpm, find the linear speed in mi
elena-s [515]

Answer:

The linear speed in which Darlene is traveling is 24.74 miles per hour.

Step-by-step explanation:

The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed (v), measured in inches per second, is defined by following expression:

v = R\cdot \omega (1)

Where:

R - Radius of the wheel, measured in inches.

\omega - Angular speed, measured in radians per second.

If we know that R = 11\,in and \omega \approx 39.584\,\frac{rad}{s}, then the linear speed, measured in miles per hour, in which Darlene is traveling is:

v = 11\,in\times \frac{1\,mi}{63360\,in} \times 39.584\,\frac{rad}{s}\times \frac{3600\,s}{h}

v \approx 24.74\,\frac{mi}{h}

The linear speed in which Darlene is traveling is 24.74 miles per hour.

8 0
3 years ago
if i got 20 on my maths test and 205 in my science and in my english i got 100 what was my total result out of 2000
laiz [17]
The answer is 325, 20 + 205 + 100 = 325
4 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

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EXPERT HELP, I'LL GIVE BRAINLIEST:
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Answer:

B or A.

Step-by-step explanation:

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