(x/2 - 3 1/3) - (x/4

Identify a possible first step using the elimination method to solve the system and then find the solution to the system. 3x + 2

ryzh [129]

ans is b...multiply first eqn by -2

=》 -6x -4y = -48...eqn 3

add eqn 2 and 3...

=》 -2y = -18

=》 y = 9...x =2

6 0

3 years ago

What is the median of the data set:348,349,354,355,357,359,360,367,37,381,386,388,388

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

median is the middle value in an ordered list of numbers.

359 is the middle value of median data.

Hope this helps!

Thanks!

7 0

3 years ago

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I know this is easy but what is 799 divided by 7

Mademuasel [1]

114.14

hope this helps.

3 0

3 years ago

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Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

A football coach walks 12 meters westward, then 16 meters eastward,

tino4ka555 [31]

Answer:

Total distance traveled = 56 m

Total displacement is 12 m

Direction of coach is westward

Step-by-step explanation:

It is given that football coach first go 12 meter westward then 16 meter eastward.

So no position of coach in eastward direction = 16 - 12 = 4 m

And then 22 m west westward

Therefore position of coach now is 22-4 = 18 m westward

And finally 6 m eastward

Therefore final position of coach is 18-6= 12 m westward

So displacement of coach is 12 m and direction is westward.

Total distance traveled = 12+16+22+6= 56 m

4 0

3 years ago

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(x/2 - 3 1/3) - (x/4 - 1 2/3)