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Colt1911 [192]
3 years ago
6

Can you please help with this.

Mathematics
2 answers:
wariber [46]3 years ago
8 0
No it is not,when the definition is separated into conditional statement is true
nlexa [21]3 years ago
7 0
Think it is A my dude
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Please this is a test
amid [387]
5

you use the formula a^2+b^2=c^2

a=3, b=4

3*3=9 and 4*4=16

16+9=25

square root of 25 is 5.


5 is the answer
7 0
2 years ago
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May you Compare v5 and 1.3
Julli [10]
I’m pretty sure it is 71
8 0
3 years ago
Evaluate p(-2)=x^3-4x-5
Pani-rosa [81]

Step-by-step explanation:

p(x) =  {x}^{3}  - 4x - 5 \\ p( - 2) =  {( - 2)}^{3}  - 4( - 2) - 5 \\  =  - 8 + 8 - 5 \\  =  - 5

3 0
3 years ago
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When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f
Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

P(A) = 0.0286 + 0.1*0.9714 = 0.12574

Probability of you winning and fireworks going off:

100% of 1/35, so P(A \cap B) = 0.0286

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275

0.2275 = 22.75% probability that you actually won that round

8 0
3 years ago
Prove the trig identity: (tanx/1+secx)+(1+secx/tanx)=2cscx
lakkis [162]
=[(sinx/cosx)/(1+1/cosx)] + [(1+1/cosx)/(sinx/cosx)]

=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]

= [sinx/(cosx+1)] + [(cosx+1)/sinx]

= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]

= [2+2cosx] / [sinx(cosx+1)]

=[2(cosx+1)] / [sinx (cosx+1)]

= 2/sinx

= 2 cscx

(I think this will be helpful for you. if you can see the picture, it has more detail in it.)

7 0
3 years ago
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