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3 years ago

How much per pound of mushrooms if 2/3 of a pound is 11.25

Mathematics

1 answer:

Anarel [89]3 years ago

3 0

Answer:

16.875

Step-by-step explanation:

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I need help with this somebody help

Mariulka [41]

Answer:

Width: x + 3

(Length, width):

(5,4) (6,5) (7,6)

Step-by-step explanation:

x² + 7x + 12

x² + 4x + 3x + 12

x(x + 4) + 3(x + 4)

(x + 4)(x + 3)

Longer one is the length,

With is (x + 3)

x = 1,

5 × 4

x = 2,

6 × 5

x = 3,

7 × 6

3 0

3 years ago

Emily took 300 US dollars to the bank to exchange it for Canadian dollars. The exchange rate on that day was 1.25 Canadian dolla

Paha777 [63]

Emily wanted to exchange her 300 US Dollars for Canadian Dollars.

The exchange rate for it was 1.25 Canadian Dollars for 1 US Dollar.

This means that 1 US Dollar = 1.25 Canadian Dollars.

So if we were to follow this pattern,

2 US Dollars = 2 × 1.25 = 2.5 Canadian Dollars

3 US Dollars = 3 × 1.25 = 3.75 Canadian Dollars

4 US Dollars = 4 × 1.25 = 5 Canadian Dollars

So for 300 US Dollars, we'll need to multiply 300 by 1.25.

300 US Dollars = 300 × 1.25 = 375 Canadian Dollars.

Hope it helps. :)

4 0

3 years ago

Simplify both please thank you

Molodets [167]

Hang on im trying...

3 0

3 years ago

#Quality answer needed #No spam _/|\_

Rina8888 [55]

Answer:

Step-by-step explanation:

Given,

Cost price of the car when Arjun bought = ₹ 3,50,000

Cost price of that same car after 1 year = ₹ 3,70,000

So,

Amount of money increased on the car's price

= ₹ (3,70,000 - 3,50,000)

= ₹ 20,000

Therefore, 

Percentage of increase on the car's price

$= \frac{20000}{350000} \times 100$

[On Simplification]

$= \frac{2}{35} \times 100$

[On further Simplification]

= 5.7142......

= 5.71 (approx.)

Hence,

Percentage in increase of car's price was 5.71% (Ans)

7 0

2 years ago

Read 2 more answers

Please help as soon as possible

ch4aika [34]

To solve this problem you must apply the proccedure shown below:

You must switch the variables, and then, you must solve for $y$ , as following:

$x=-\frac{1}{2} \sqrt{y} +3\\ (x-3)^{2} = (\frac{1}{2}\sqrt{y})^{2} \\ y=4x^{2} -24x+36\\ f^{-1} (x)=4x^{2} -24x+36$

Therefore, as you can see, the answer is: $f^{-1} (x)= 4x^{2} -24x+36
$

8 0

3 years ago