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svetlana [45]
3 years ago
12

I need help .Can you do Questions 1,2,3,4,5,6 and 7 Please?

Mathematics
1 answer:
barxatty [35]3 years ago
5 0
1-

a. 16 b. 81 c.5 d.8





2-

a. 3

b. 30





3-


a. 50.7. b. 729 c. 6.7 d. 7.7







4-


a. 289


b. 2197





5.


a.
{5}^{2}  \times  {2}^{2}  = 10 {}^{2}


b.
0.3 \times  {10}^{3}  = 300





6-


a.
4 {}^{2} \times  {2}^{3}  -  \sqrt{25}  = ( {2}^{2}) {}^{2}  \times  {2}^{3}  - 5  \\  =  {2}^{4}  \times  {2}^{3}  - 5 =  {2}^{7}  - 5



b.
\sqrt{100 }  \times   \sqrt[3]{64} = 10 \times 4 = 40




c.
3( {7}^{2}  -  \sqrt{81}) = 3( {7}^{2}  - 9)  \\ = 3(49 - 9) = 3 \times 40 = 120






7.
{2}^{3}  \times {3}^{2}







good luck
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Need help with this one as well I would be very grateful please need help !
hram777 [196]
You are given two x and y pairs: (100,45) and (570,162.5)
First solve for the slope, m.

m = (162.5 - 45) / (570 - 100)
m = 117.5 / 470
m = 0.25

Not only is "m" the slope but it is the rate (dollars per minute) in the question. So it's 25 cents per minute to use the phone.
After imputing "m"  the linear equation looks like this:
y = 0.25x + b

Use either point as (x,y) to solve for the y-intercept "b". I'll use (100,45)

45 = 0.25(100) + b
45 = 25 + b
45 - 25 = b
20 = b

Not only is "b" the y-intercept but it is also always the flat fee added on to linearly increasing cost questions like this.

Final equation is:
y = 0.25x + 20

Part B.) If 939 minutes are used. Just put that in for x and solve for y.

y = 0.25(939) + 20
y = 234.75 + 20
y = 254.75

8 0
3 years ago
What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

7 0
3 years ago
What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?
Kay [80]

Answer:

hello your question is incomplete attached below is the complete question

answer : -2400 π

Step-by-step explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt = d(\pi r^h ) / dt  

              = \pi h\frac{d(r^2)}{dt}  = -\pi h *2r *dr/dt

hence ; dv / dt = -2400 π

3 0
2 years ago
Help me please due in 20 minutes
Kamila [148]

Answer:

y=4

Step-by-step explanation:

4 0
2 years ago
7is subtracted from the quotient of 48 divided by th<br>e sum of 5 &amp; difference of 11 and 8​
kramer

Answer:

7-48=41

÷

5+11-8

bodmas

5+3=8

41÷8=5.125

5 0
3 years ago
Read 2 more answers
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