Answer:
– 21x^3 y – 9x^2 y^2 e) is your answer
Step-by-step explanation:
Solve the following system for A and B:
{A = 7 x^2 + 3 x y
B = -3 x y
Express the system in matrix form:
(1 | 0
0 | 1)(A
B) = (7 x^2 + 3 x y
-3 x y)
Write the system in augmented matrix form and use Gaussian elimination:
(1 | 0 | 7 x^2 + 3 x y
0 | 1 | -3 x y)
Collect results:
Answer: {A = 7 x^2 + 3 x y , B = -3 x y
then we multiply the results (7 x^2 + 3 x y) ( -3 x y) = – 21x^3 y – 9x^2 y^2
{12x 4y = 15232x 12y = 42012x 4y = 15232x 12y = 420?In the equations, xx represents the cost of a chicken lunch and yy represents the cost of a v.... I think... "Xx represents the cost of a chicken lunch..."
9514 1404 393
Answer:
zeros: {-2, 1, 5}
Step-by-step explanation:
A graphing calculator works nicely for identifying turning points, roots, increasing/decreasing intervals, and more.
V1 - velocity first train
v2 - velocity second train
v2 > v1
v2 - v1 = 17 mph
We know, that:
![s_1+s_2=210 \ [miles] \\ \\ t_1=t_2=2h](https://tex.z-dn.net/?f=s_1%2Bs_2%3D210%20%5C%20%5Bmiles%5D%20%5C%5C%20%5C%5C%20t_1%3Dt_2%3D2h)
So:

NOw we've got simple system of equations:
![+\begin{cases} v_2-v_1=17 \\ v_2+v_1=105\end{cases} \\ \\ 2v_2=122 \qquad /:2 \\ \\ v_2=61 \qquad [mph] \\ \\ v_2-v_1=17 \\ \\ 61-v_1=17 \\ \\ v_1=44](https://tex.z-dn.net/?f=%2B%5Cbegin%7Bcases%7D%20v_2-v_1%3D17%20%5C%5C%20v_2%2Bv_1%3D105%5Cend%7Bcases%7D%20%5C%5C%20%5C%5C%202v_2%3D122%20%5Cqquad%20%2F%3A2%20%5C%5C%20%5C%5C%20v_2%3D61%20%5Cqquad%20%5Bmph%5D%20%5C%5C%20%5C%5C%20v_2-v_1%3D17%20%5C%5C%20%5C%5C%2061-v_1%3D17%20%5C%5C%20%5C%5C%20v_1%3D44)
Velocities of these trains are 61mph and 44mph
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