Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
I can't get the thing to copy or put a picture down. But, I think the answer is C. I'm not good at math. But, Lemme know if I have that one wrong!
- Martiinez ;)
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4) 
Multiply by 2 on both sides
3m + 15 = 45
Subtract both sides by 15
3m = 30
Divide both sides by 3
so m = 3
5) 
Multiply both sides by 8
168 = q + 35
Subtract both sides by 35
q = 133
6) 
Subtract 14 from both sides
multiply by -11 on both sides
4x = 572
Divide both sides by 4
x= 143
7) 
Add 6 on both sides
Multiply both sides by 5
3c = 75
Divide both sides by 3
c = 25
8) 
Subtract both sides by 17
Multiply both sides by -2
t = -52
9) 
Multiply both sides by -7
42= 5p + 2
subtract 2 from both sides
40 = 5p
Divide both sides by 5
so p = 8
Answer:
one time
Step-by-step explanation:
because after that you would subtract by 20
Answer:
1080 in^2
Step-by-step explanation:
