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djyliett [7]
3 years ago
8

On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the per

cent of scores that are: a) Between 90 and 100
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

34.134%

Step-by-step explanation:

Given :

Normal distribution ;

Mean, m = 100 ; Standard deviation, s = 10

Percentage score between 90 and 100

P(90 ≤ x ≤ 100)

Recall : Zscore = (x - m) / s

P[(90 - 100) / 10 ; (100 - 100) / 10]

P[(10/10 ; 0 / 10)]

P(Z ≤ 1) - P(Z≤0) (Using Z probability calculator)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

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Anna11 [10]
Simple,

since he has no money to begin with just write your equation..

E=6s

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E=6(1)
E=$6

If he sells 2 shirts:

E=6(2)
E=$12

And so on and so forth, thus, your equation is E=6s.
4 0
3 years ago
In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

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3 years ago
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coldgirl [10]

Answer:

165 hits

Step-by-step explanation:

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20(40)
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How do you calculate elapsed time?
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First tell me what elapsed time is
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