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4 years ago

Ms. Ziolkowski asks her class to write the correct trigonometric function for the triangle shown below.

Mathematics

2 answers:

devlian [24]4 years ago

8 0

Answer:

Both are correct

Step-by-step explanation:

They just chose different reference angles to find the ratio.

Rihanna chose angle A:

tan A = opposite/adjacent

tan A = 3/4

Christopher chose angle C:

tan C = opposite/adjacent

tan C = 4/3

max2010maxim [7]4 years ago

7 0

Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:

SOH

CAH

TOA

This means:

Sine --> Opposite/Hypotenuse

Cosine --> Adjacent/Hypotenuse

Tangent --> Oppositie/Adjacent

With that in mind, number 1:

Would be Sine, or C.

Number 2 would be, Cosine, or E.

And number 3 would be Tangent, or B.

Hope that was helpful.

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SSSSS [86.1K]

Answer:

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Step-by-step explanation:

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3 years ago

What are the solutions of the equation (x - 3)2 + 2(x - 3) - 8 = 0? Use u substitution to solve.

allochka39001 [22]

The answer is x= -1 and x=5

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3 years ago

Two parabolas have the same focus, namely the point $(3,-28).$ Their directrices are the $x$-axis and the $y$-axis, respectively

jeyben [28]

Answer:

the slope of the common cord is: $-1$

Step-by-step explanation:

Given the focus (a,b) = (3,-28)

for a parabola with directrix at x-axis the equation will be

$\left(x-a\right)^{2}+\left(y-b\right)^{2}=y^{2}$

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-y^{2}=0$

for a parabola with directrix at y-axis the equation will be

$\left(x-a\right)^{2}+\left(y-b\right)^{2}=x^{2}$

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-x^{2}=0$

The common chord is the line between two points where the two parabolas intersect. For intersection, we can equate the two parabolas!

In other words, at the point of intersection of these two parabolas the values of the two parabolas will be the same.

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-y^{2}=\left(x-a\right)^{2}+\left(y-b\right)^{2}-x^{2}$

$\left(x-3\right)^{2}+\left(y+28\right)^{2}-y^{2}=\left(x-3\right)^{2}+\left(y+28\right)^{2}-x^{2}$

we can now simplify the equation. (we can see that (x-3) and (y+28) both cancel out by -(x-3) and -(y+28))

$-y^{2}=-x^{2}$

$y=\sqrt{x^{2}}$

$y=\pm x$

this the equation of the common cord. but we need to select whether its

$y=+ x$ or $y=-x$ .

This can be found by realizing that the focus lies on the 4th quadrant of the xy-plane! And the equation $y=-x$ also generates a line that exists in the 2nd and 4th quadrant.

Hence the slope of the common cord is the slope of the line $y=-x$

that is : $-1$

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3 years ago

What is 2 more tens than 11?

svet-max [94.6K]

The answer would be 31

8 0

3 years ago

Read 2 more answers

What are the solutions of 12 - x ^ 2 = 0 ? X = 2sqrt(3) and x = - 2sqrt(3) x = 3sqrt(2) and x = - 3sqrt(2) x = 4sqrt(3) x = - 4s

Jet001 [13]

Answer:

A. $x = 2\sqrt{3}$ and $- 2 \sqrt{3}$

Step-by-step explanation:

The equation is:

$12 - x^2 = 0$

To solve this, move 12 to the right hand side and find its square root:

$12 = x^2\\\\=> x^2 = 12\\\\x = \sqrt{12}$

The square root of a number has two answers, a negative and a positive number of the same value:

=> $x = 2\sqrt{3}$ and $- 2 \sqrt{3}$

3 0

3 years ago

Read 2 more answers