Find the depth of the river at 9 hours and 18 hours by seeing where the line is on the Y axis.
At 9 hours the river is 18 feet deep
At 18 hours the river is 21 feet deep.
The average rate of change is the change in Y over the change in X
The Y is the depth and the X is the time:
(21-18) / (18-9) = 3/9 = 1/3 = 0.33
The average rate of change is 0.3 foot per hour. ( Rounded to nearest tenth)
Answer:
Option c. 81/2
Step-by-step explanation:
Fifth term: a5=?
First term: a1=8
Common ratio: r=3/2
an=a1*r^(n-1)
with n=5
a5=a1*r^(5-1)
a5=a1*r^4
Replacing the known values:
a5=8*(3/2)^4
a5=8*(3)^4/(2)^4
a5=8*81/16
Simplifying: Dividing the numerator and denominator by 8:
a5=(8*81/8)/(16/8)
a5=81/2
Answer: Option c. 81/2
Answer:
ΔPTS≅ΔRTA by AAS axiom of congruency
Step-by-step explanation:
Consider ΔPQA and ΔRQS
∠PQA=∠RQS (Vertically Opposite Angles)
∠QAP=∠QSR (Complementary of two equal angles, ∠RAT and∠PST)
Due to angle sum property of a triangle, we come to the conclusion that
∠APQ=∠SRQ
Consider ΔPTS and ΔRTA
TA=TS (Given)
∠RAT=∠PST(Given)
∠APQ=∠SRQ (Proved above)
Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.
