If you mean by simplifing it then it must be 4/11
Answer:
104degrees
Step-by-step explanation:
From the given diagram, line LJ bisects KN, hence arcKL = arcHJ
Given
arHJ = 4x
arc KJ = x+39
Equating both
4x = x+39
4x - x = 39
3x = 39
x = 39/3
x = 13
Since arcHK = arcHJ + arcKJ
arcHK = x+39+4x
arcHK = 5x+39
arcHK = 5(13) + 39
arcHK = 65+39
arcHK = 104degrees
Hence the measure of arcHK is 104degrees
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's
2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside
2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25
that is a circle center (2,-2.5) with radius √9.25
Well it is true if the problem is the right with the right answer. If not you have a false eqaution.
