First question
42 students
Second question 65%
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Y > x
y = 2(3+x)
y = 3x-2
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2(3+x) = 3x-2
2(3+x) - (3x-2) = 0
6 + 2x -3x + 2 = 0
8 -x = 0
x = 8
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y = 2(3+x) = 2(3+8) = 22
y = 3x-2 = 3*8 -2 = 22
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x = 8 ; y = 22
This question is asking you for the least common multiple of 60 (seconds in 1 minute) and 24 (seconds in 24 seconds).
I think it's 120 (you should check it) and that would be 3 minutes.
