Answer:
The linear regression equation that represents the set of data is:

The predicted number of new cases for 2013 is 1368.
Step-by-step explanation:
The general form of a linear regression is:

Here,
<em>y</em> = dependent variable
<em>x</em> = independent variable
<em>a</em> = intercept
<em>b</em> = slope
Compute the values of <em>a</em> and <em>b</em> as follows:

The linear regression equation that represents the set of data is:

Compute the predicted value of the number of new cases for 2013 (i.e. <em>x</em> = 12) as follows:


Thus, the predicted number of new cases for 2013 is 1368.
2f+6+4f=6+6f
6f+6-6=6-6+6f
6f=6f
This means f can equal any number which we call mathematically infinite solution or infinitely many solutions
Answer:
90 liters
Step-by-step explanation:
It's given in the question!