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Nutka1998 [239]
3 years ago
5

BRAINLIEST if right!

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0
Y=-1/3x-1.
Hope this helps!
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A large polar bear may weigh 1600 pounds.What fractional part of a ton is 1600 pounds?
Alenkinab [10]
A ton is 2000 lbs. If a polar bear is 1600 lbs then the fractional part of a ton would be...

1600/2000 which will reduce to

16/20 = 4/5
8 0
3 years ago
Read 2 more answers
Algebraically determine the zeros of the quadratic function g(x)= x^2+7x+12. Show all work please
Alinara [238K]

Answer:

x = - 4, x = - 3

Step-by-step explanation:

To find the zeros equate f(x) to zero, that is

x² + 7x + 12 = 0

To factorise the quadratic

Consider the factors of the constant term (+ 12) which sum to give the coefficient of the x- term (+ 7)

The factors are + 4 and + 3, since

4 × 3 = 12 and 4 + 3 = 7, hence

(x + 4)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x + 3 = 0 ⇒ x = - 3

5 0
4 years ago
In the kite , AK=9 , JK=15 , and AM=16 .
Veronika [31]

Answer:

The Length of JM is 20.

Step-by-step explanation:

Given,

JKLM is a kite in which JL and KM are the diagonals that intersect at point A.

Length of AK = 9    

Length of JK = 15  

Length of AM = 16

Solution,

Since JKLM is a kite. And JL and KM are the diagonals.

And we know that the diagonals of a kite perpendicularly bisects each other.

So, JL ⊥ KM.

Therefore ΔJAK is aright angled triangle.

Now according to Pythagoras Theorem which states that;

"The square of the hypotenuse is equal to the sum of the square of base and square of perpendicular".

JK^2=KA^2+AJ^2

On putting the values, we get;

(15)^2=9^2+AJ^2\\\\225=81+AJ^2\\\\AJ^2=225-81=144

On taking square root onboth side, we get;

\sqrt{AJ^2} =\sqrt{144}\\\\AJ=12

Again By Pythagoras Theorem,

AJ^2+AM^2=JM^2

On putting the values, we get;

JM^2=(12)^2+(16)^2\\\\JM^2=144+256=400

On taking square root onboth side, we get;

\sqrt {JM^2}=\sqrt{400}\\\\JM=20

Hence The Length of JM is 20.

4 0
3 years ago
The perpendicular bisector of the line segment connecting the points $(-3,8)$ and $(-5,4)$ has an equation of the form $y = mx +
docker41 [41]

Answer:

m = -1/2 and b = 6.5

Step-by-step explanation:

To find the slope of the original line segment, we have to do the change in y/the change in x:

(4-8)/(-5--3) = -4/-2 = 2

2 is the slope of the original line segment, but since this is the perpendicular bisector, we have to take the negative reciprocal of 2 so m = -1/2

To find b we substitute the values of x, y, and m into the equation. Let's use the x value of -3 and the y value of 8:

y = mx + b

8 = -1/2(-3) + b

8 = 3/2 + b

6.5 = b

5 0
4 years ago
If an object has a mass of 12Kg on Earth, what would its mass be on the Moon and Mars?
Leviafan [203]

Answer:

mars = 4.54 kg and moon = 1.98 kg

Step-by-step explanation:

12 kg on mars =  4.54 kg

12 kg on moon =  1.98 kg

6 0
3 years ago
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