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3 years ago

Solve for x.

Mathematics

2 answers:

grigory [225]3 years ago

7 0

Answer:

x=9

Step-by-step explanation:

x+3=12

x+3-3=12-3

x=9

zubka84 [21]3 years ago

3 0

The correct answer is 9

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Divide. Express your answer in lowest terms. 1/8 Divided by 4 =

Yuliya22 [10]

$\sf\dfrac{1}{8}\div4$

Find the reciprocal of 4 and multiply.

$\sf\dfrac{1}{8}\times\dfrac{1}{4}$

Multiply the numerators and denominators together:

$\boxed{\sf\dfrac{1}{32}}$

5 0

4 years ago

Read 2 more answers

Can someone help me with this? Preferably with an explanation on how to actually figure this out. Thank you!

zhannawk [14.2K]

Answer:

2^-4, 1/16, (1/2)^4

There is a rule with exponents, if you are dividing two exponents you subtract the first exponent from the other to simplify it, also meaning it's equivalent.

So in this case 5-9 = 2^-4

The others were found by evaluation.

5 0

3 years ago

Arun spent 25% of his pocket money and has Rs 125 left how much had he at first

Nonamiya [84]

Answer:

Rs166.67

Step-by-step explanation:

Let

x -----> amount of money Arun has in his pocket at the beginning

we know that

100%-25%=75%

75%=75/100=0.75

The linear equation that represent this situation is

0.75x=125

Solve for x

Divide by 0.75 both sides

x=125/0.75

x=Rs166.67

8 0

4 years ago

ANSWER QUICK FOR BRAINLIEST!! please i need this asap:))

LiRa [457]

Answer:4

Step-by-step explanation: please just trust me!

7 0

3 years ago

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago