The domain is hope this helped:)
Answer:
53
Step-by-step explanation:
when c=6 and d=5 we want to substitute the variables with the numbers in the equation so we'll have
(5) + 8(6)
after evaluating we come up with the answer 53
Answer:
a) 236/100 = 2.36
b) 101/100 = 1.01
c) 814/100 = 8.14
Step-by-step explanation:
The divisor in each case is already a factor of 100, so multiply the numerator and denominator by the number that will make the denominator 100. Then add 100 times the integer to the numerator of the fraction.
a) 2 9/25 = (200 +9·4)/(25·4) = 236/100 = 2.36
b) 1 1/100 = (100 +1)/100 = 101/100 = 1.01
c) 8 7/50 = (800 +7·2)/(50·2) = 814/100 = 8.14
____
Since each of these fractions has a denominator of 100, the decimal can be written by putting the least significant digit of the numerator in the hundredths place of the decimal number.
For example, for 236/100, putting 6 in the hundredths place puts 3 in the tenths place and 2 in the units place for a decimal number of 2.36.
The answer is expressions D, E, and G.
In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.
Options A and B only have 1 term, an x or y³, so these are incorrect.
Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.
D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.
G has 3 unique terms, x³, x^4, and 7x, so this is correct.
When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.
I hope this helps!
