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Doss [256]
4 years ago
13

Determine the exact value of sin 150 degrees

Mathematics
1 answer:
avanturin [10]4 years ago
7 0

Answer:

\frac{1}{2}

Step-by-step explanation:

Use the identity:

\sin(180-\theta)=\sin \theta

We were given:\sin 150\degree

We can rewrite this as:

\sin(180-30)\degree=\sin 30\degree

On the unit circle, \sin 30\degree=\frac{1}{2}

This implies that:

\sin(180-30)\degree=\sin 150\degree=\sin 30\degree=\frac{1}{2}

Therefore the exact value of \sin 150\degree is \frac{1}{2}

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A table contains the ordered pairs (3, 42.25) and (5, 50.75). If the relationship in the table is linear, explain how to find th
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Answer:

The initial value is 29.5

Step-by-step explanation:

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept ( also called initial value)

we have the points

(3,42.25) and (5,50.75)

Find the slope m

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{50.75-42.25}{5-3}

m=\frac{8.5}{2}

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substitute in the equation

y=4.25x+b

<em>Find the value of b</em>

with the point (3,42.25)  ( or the other given point)

substitute the value of x and the value of y in the equation and solve for b

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substitute

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