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DENIUS [597]
4 years ago
8

Endpoint (-10,9); midpoint (2,5)

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
4 0
<u>x₂ + x₁</u> = m         <u>y₂ + y₁</u> = m<u>
</u>    2                         2
<u>
</u>-10 = x₂
<u />9 = y₂

2=m
5=m

Plug in given numbers

<u>-10 + x</u> = 2                <u>9 + y</u><u /> = 5
      2                              2
Solve

<u>-10 + x</u> = 2*2
     2 *2

-10 + x = 4
+10        +10
         x = 14
(9 + y)/2(2) = 5 (2)
9 + y = 10
-9         -9
      y=1

Final Answer: (14,1)




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Answer:

the first one

Step-by-step explanation:

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-1/2x+12=-16 1/2 help<br> Plz I need it quick
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Subtract 12 from both sides
- \frac{1}{2} x+12-12=-16 \frac{1}{2} -12- \frac{1}{2}x=-28 \frac{1}{2}
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7 0
4 years ago
-20÷5(-3)+4(-2)(-1)-4²<br>step by step please and thank you!​
disa [49]

\huge \boxed{\mathbb{QUESTION} \downarrow}

\large \tt \: -20 \div  5(-3)+4(-2)(-1)-4  ^ { 2  }

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\tt \: -20 \div  5(-3)+4(-2)(-1)-4  ^ { 2  }

Divide -20 by 5 to get -4.

\tt \: -4\left(-3\right)+4\left(-2\right)\left(-1\right)-4^{2}

Multiply -4 and -3 to get 12.

\tt \: 12+4\left(-2\right)\left(-1\right)-4^{2}

Multiply 4 and -2 to get -8.

\tt \: 12-8\left(-1\right)-4^{2}

Multiply -8 and -1 to get 8.

\tt \: 12+8-4^{2}

Add 12 and 8 to get 20.

\tt \: 20-4^{2}

Calculate 4 to the power of 2 and get 16.

\tt \: 20-16

Subtract 16 from 20 to get 4.

=  \boxed{\boxed{ \bf 4}}

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3 years ago
ARI
umka21 [38]
0 or if maybe another 0 for two ZER0s
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4 years ago
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