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4 years ago

15 points! :)

Mathematics

1 answer:

SVEN [57.7K]4 years ago

8 0

Answer:

10) 1/7

11) 3/4

12) 1/3

13) 1/2

14) 1/2

15) 7/9

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Noah and Lin are making paper cones to hold popcorn to hand out at parent math night. They want the cones to hold 9 cubic inches

DanielleElmas [232]

Answer:

So, The possible values of h and r are

1. r = 3 , h = 3

2. r = 1, h = 27

3. r = 2, h = 6.75

Step-by-step explanation:

P.S - The exact ques is -

As we know that Volume of cone , V = $\frac{1}{3}\pi r^{2}h$

As given,

V = $9\pi$

⇒ $\frac{1}{3}\pi r^{2}h = 9\pi \\ \frac{1}{3} r^{2}h = 9 \\r^{2}h = 27$

So,

The possible values of h and r are

1. r = 3 , h = 3

2. r = 1, h = 27

3. r = 2, h = 6.75

In Case I-

When r = 3, h = 3

(3)² ×3 = 9×3 = 27

Satisfied

Case II-

r = 1, h = 27

(1)²×27 = 1×27 = 27

Satisfied

Case III-

r = 2, h = 6.75

(2)²×6.75 = 4×6.75 = 27

Satisfied

8 0

3 years ago

Simplify 6^7/6^5 in index form

Oksanka [162]

Answer:

6²

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ ⇔ $a^{(m-n)}$ , then

$\frac{6^{7} }{6^{5} }$

= $6^{(7-5)}$

= 6²

6 0

3 years ago

Read 2 more answers

I'll pick brainiest. Please help me!! Answer as best as you can. THANK YOU!!

rodikova [14]

The volume of the cube is 54.87 but rounded to the nearest tenth is 54.9

The exact volume of the cylinder is 1770.28 but rounded is 1770.29 and the approximate volume of the cylinder is 1769.36

5 0

3 years ago

On a calendar of 31 days what are the prime numbers

zepelin [54]

I believe <span>2 3 5 7 11 13 17 19 23 29 31</span>

5 0

3 years ago

Read 2 more answers

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0

1 year ago