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mafiozo [28]
2 years ago
15

What is the area of the semicircle (use 3.14 for p)? Please help! Will mark brainlyest.

Mathematics
2 answers:
Andrei [34K]2 years ago
7 0

Answer: the first option: 127.17cm2

Step-by-step explanation:

1. divide the diameter in half to get the radius.

2. multiply the radius squared by pie

3. divide that answer in half

so:

9*9=81

81*3.14= 254.34

254.34/2= 127.17

Marizza181 [45]2 years ago
4 0

Answer:

127.17 cm²

Step-by-step explanation:

  • Area of a semicircle: 1/2*π*r²
  • π (pi) = 3.14
  • r (radius) = d (diamater) / 2 => 18/2 = 9 cm

A = 1/2*π*r²

A = 1/2*3.14*9²

A = 1/2*3.14*81

A = 3.14*40.5

A = 127.17 cm²

Therefore, the area of the semicircle is 127.17 cm²

Hope this helps!

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Answer:

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y = 2/3x + 6

y = –1/3x – 4

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Correct answer:

y = 3x + 2

Explanation:

Convert the equation to slope intercept form to get y = –1/3x + 2.  The old slope is –1/3 and the new slope is 3.  Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

With the new slope, use the slope intercept form and the point to calculate the intercept: y = mx + b or 5 = 3(1) + b, so b = 2

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3 years ago
Sharla’s recipe for 4 servings of stew has 2 potatoes and 4 celery sticks. How many potatoes and celery sticks does she need to
kumpel [21]

Answer:

4 servings : 2 potatoes and 4 celery sticks. Find the number of potatoes and celery sticks in 6 servings. 6/4 = 1.50 2 potatoes x 1.50 = 3 potatoes 4 celery sticks x 1.50 = 6 celery sticks 6 servings of stew has 3 potatoes and 6 celery sticks. Other way of computing for the 6 servings is getting the number of potatoes and celery sticks per serving.

Step-by-step explanation:

5 0
2 years ago
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Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
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Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

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7 0
3 years ago
Determine the volume of the tent?
katovenus [111]

Answer:

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