Question

I need help with the follow question.

Answer 1

Answer:

$x=0,y=2$

Step-by-step explanation:

Given equation:

          $2x + 4y = 8$    Equation:1

         $x = 3y-6\\or\\x-3y=-6$    Equation:2

Multiplying equation:2 by 2 gives:

          $2x-6y=-12$   Equation:3

Subtracting Equation:3 from Equation:1

            $2x + 4y-(2x-6y) = 8-(-12)$

The negative sign outside the bracket changes the sign inside it after opening the bracket

         $2x+4y-2x+6y=8+12$

                   $10y=20\\\\y=2$

Putting the value of 'y' in Equation:2

                            $x-3y=-6\\x-3(2)=-6\\x-6=-6\\x=-6+6\\x=0$

$x=0,y=2$