use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²
we need AD and DC
so
AD²+7.9²=9.4²
AD=√25.95
DC²+7.9²=23.2²
DC=√475.83
so
AD+DC=base=(√25.95)+(√475.83)≈26.9076
AC≈26.91 units
The correct answer is b because the number increases by 4 every time
hope I helped
Solution is where the 2 lines intersect
I would say the answer is 3rd option, whre both lines pass through that point
angle 1 = 180° - 115° (Linear Pair)
<u>angle 1 = 65°</u>
<u>angle 2 = angle 1 = 65°</u> ( Angles on the equal sides of an isosceles triangle )
angle 3 = 180° - (65° + 65°) (Angle Sum Property)
angle 3 = 180° - 130°
<u>angle</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>5</u><u>0</u><u>°</u>
angle 4 = 180° - 65° (Linear Pair)
<u>angle</u><u> </u><u>4</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u>
<u>angle</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u> (Vertically Opposite Angles)
A=.5*r^2*theta
a=p
2.5q=2pi(r)
2pi(r)=.5(r^2)(2pi)
1=.5r
2=r