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sleet_krkn [62]

3 years ago

15

What property is ( 18 - 3x ) + 3x = 18 + ( -3x + 3x )

2 answers:

scoundrel [369]3 years ago

7 0

Associative property of addition<span />

Andre45 [30]3 years ago

7 0

Associtaivie property or however u spell it lol

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the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0. What is the value of q?the equation -2x^2+3=-9x is rewritte

Novosadov [1.4K]

Value of q is $\frac{105}{8}$ .

<u>Step-by-step explanation:</u>

We have , the equation $-2x^2+3=-9x$ is rewritten in the form of $-2(x-p)^2 +q=0$ . We need to find What is the value of q . Let's find out:

Let's simplify equation $-2x^2+3=-9x$ into $-2(x-p)^2 +q=0$ :

⇒ $-2x^2+3=-9x$

⇒ $-2x^2+9x+3=0$

⇒ $2x^2-9x=3$

⇒ $2(x^2-\frac{9}{2}x)=3$

⇒ $(x^2-\frac{9}{2}x)=\frac{3}{2}$

⇒ $(x^2-2(1)\frac{9}{4}x)=\frac{3}{2}$

⇒ $(x^2-2(1)\frac{9}{4}x) + (\frac{9}{4})^2=\frac{3}{2} + (\frac{9}{4})^2$

⇒ $(x-\frac{9}{4})^2=\frac{3}{2} + (\frac{81}{16})$

⇒ $(x-\frac{9}{4})^2=\frac{24}{16} + (\frac{81}{16})$

⇒ $(x-\frac{9}{4})^2=\frac{105}{16}$

⇒ $-2(x-\frac{9}{4})^2=-2(\frac{105}{16})$

⇒ $-2(x-\frac{9}{4})^2=-\frac{105}{8}$

⇒ $-2(x-\frac{9}{4})^2+\frac{105}{8} = 0$

Comparing this equation to $-2(x-p)^2 +q=0$ , $q =\frac{105}{8}$ .

Therefore ,Value of q is $\frac{105}{8}$ .

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Step-by-step explanation:

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g(x) ≠ 0

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