Help idk how to do this

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

y = 62°

Step-by-step explanation:

z represents the mid segment of the triangle.

Since, midsegment is parallel to the third side of the triangle.

$\therefore \: y = 62 \degree...(correspnding \: \angle s) \\$

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I don't kind fast food sells large burgers for five dollars each and french fries for three dollars each that day they sold six

lesya692 [45]

Answer:

They sold 16 French fries.

Step-by-step explanation:

Let x represent the number of large burgers that they sold on that day.

Let y represent the number of French fries that they sold on that day.

fast food sells large burgers for five dollars each and french fries for three dollars each that day and their total sales was $98.It means that

5x + 3y = 98 - - - - - - - - - - - - - -1

they sold six more french fries than burgers. It means that

y = x + 6

Substituting y = x+ 6 into equation 1, it becomes

5x + 3(x + 6) = 98

5x + 3x + 18 = 98

8x = 98 - 18 = 80

x = 80/8 = 10

y = x + 6 = 10 + 6

y = 16

4 0

3 years ago

HELP HELLP HELP MEH I NEED 16 MORE CLASSES LEFT FOR SCHOOL LET IT BECOME 15 PLEASE

vodomira [7]

Answer:

2*2*9+4*12*3=36+144=180

Step-by-step explanation:

8 0

3 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

Find the product.<br><br>(0.5n 5)2(10n 7) 3

sergejj [24]