Answer:
Option 2 is the correct answer
Step-by-step explanation:

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

19.8m²
Work:
First you split the shape into a rectangle and a triangle. So now you have a triangle with the sides 4 x 3.6 and a triangle with the sides 4 x 2.7.
Side note: 2.7 comes from subtracting 3.6 off of 6.3.
Rectangle:
A = lw
A = 4 (3.6)
A = 14.4m²
Triangle:
A = 1/2lw
A = 1/2 (4) (2.7)
A = 5.4m²
Then you add the areas of both the rectangle and the triangle together.
14.4 + 5.4 = 19.8m²
I'm pretty sure it C since line L and line M are parallel
30 girls , 12 were selected
40 boys, 16 were selected
We can simplify these down by finding the Greatest Common Factor in both girls and boys:
30:12 .... 15:6 .... 1 : 2.5 30/12 .... 15/6 .... 2.5
40:16 .... 20:8 .... 1 : 2.5 OR 40/16 .... 20/8 .... 2.5
They are equal ratios because their most simplified ratios/fractions are equivalent