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3 years ago

Find the fractional notation for the ratio 5 to 9

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

5:9 is just 5/9
Hope this helps!

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Find the missing value (9,5)and (x,6)

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10.8. Multiply 6 by 9/5. Put the fractions into decimals and they both turn out to be 1.8.

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1. Which statements are true?

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3 years ago

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Wheres the question lol..

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B5%7D%20%3D%209%20-%20%20%5Cfrac%7Bx%7D%7B2%7D%20" id="TexFormula1" title=

Ray Of Light [21]

Add $\frac{x}{2}$ to both sides:

$\dfrac{2x}{5}+\frac{x}{2} = 9$

Add the fractions in the left hand side:

$\dfrac{2x}{5}+\frac{x}{2} = \dfrac{4x}{10}+\frac{5x}{10}=\dfrac{9x}{10}$

So, the equation becomes

$\dfrac{9x}{10}= 9$

Multiply both sides by 10:

$9x = 90$

Divide both sides by 9:

$x = 10$

5 0

4 years ago

Determine whether the graph of the equation is symmetric with respect to the y-axis, the x-axis, the origin, more than one of th

Murrr4er [49]

$\bf x^2y^2+3xy=1\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for x-symmetry}}{y=-y}}{x^2(-y)^2+3x(-y)=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\$

$\bf \stackrel{\stackrel{\textit{test for y-symmetry}}{x=-x}}{(-x)^2y^2+3(-x)y=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for origin-symmetry}}{x=-x~~y=-y}}{(-x)^2(-y)^2+3(-x)(-y)=1}\implies x^2y^2+3xy=1\impliedby 
\begin{array}{llll}
origin\\symmetry
\end{array}$

so, recall, the function has symmetry when the yielded resulting function resembles the original function, after negativizing the variable(s).

Also recall that minus*plus is minus, and minus*minus is plus.

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4 years ago