Question

A gram of gasoline produces 45.0kJ of energy when burned. Gasoline has a density of 0.77/gmL. How would you calculate the amount of energy produced by burning 5.2L of gasoline? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Answer 1

Answer:

Math expression: $=\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ$

Explanation:

Given:

Energy produced per gram of gasoline = 45.0 kJ

Density of gasoline = 0.77 g/ml

Volume of gasoline = 5.2  L=5200 ml

To determine:

The amount of energy produced by burning 5.2 L gasoline

Calculation set-up:

1. Calculate the mass (m) of gasoline given the density (d) and volume (v)

$m = d*v\\\\m = 0.77 g/ml*5200 ml$

2. Calculate the amount of energy produced

$=\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ=180180 kJ$