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Alika [10]
2 years ago
7

Three married couples go to a movie theater. if they sit together in a row of 6 empty seats, find the probability that each woma

n is to the left of her husband.
Mathematics
1 answer:
Ganezh [65]2 years ago
5 0

Given are three married couples.

So, let us assume there are 3 men and 3 women

They are sitting in a row of 6 empty seats

There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is 3*2*1

So, number of ways is 3! = 3*2*1 = 6 ways.

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The difference of two numbers is 90 and their quotient is 10
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To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10


Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

-------

Answer: The numbers are 100 and 10</span>
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