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Maurinko [17]
2 years ago
6

Please help me with the question y’all I really had a bad day today and I’m just really trying to pass my assignments please jus

t one question please y’all

Mathematics
1 answer:
OLga [1]2 years ago
4 0
(I don’t know how to right the angle signs on this keyboard, so just a heads up)

Measure Angle 1 = 60°
Measure Ange 2 = 30°


(These im not totally sure, I’m just assuming because i don’t think there’s enough information)

Measure Angle 3 = 60°
Measure Angle 5 = 40°
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Write the inverse of the conditional statement.
Maslowich
The answer is a I'm pretty sure
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3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

1/3 of a mile / 1/16 of an hour = MPH. In order to divide fractions you flip the bottom fraction and multiply across. 1/3 / 1/16 = 1/3 * 16/1 = 16/3 = 5 1/3 = 5.33mph

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Concept 44: I can determine the circumference of a circle and use the circumference of a circle to find its diameter and radius.
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Answer:

Step-by-step explanation: to find circumference, u do 2*pi*radius or pi times diameter

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