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yawa3891 [41]
3 years ago
8

Savings account A has 1500 and pays 3.5% interest yearly. Savings account B has 1400 and pays 4% interest yearly. the savings ac

count that earned the most interest after one year is savings account.
Mathematics
2 answers:
Alex73 [517]3 years ago
7 0
To find these numbers, we do this:
Savings Acc A:
1.35(1500) = 2025
Savings Acc B:
1.04(1400) = 1456
Savings Account A has earned the most interest.
Rina8888 [55]3 years ago
7 0

so whats the question

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nasty-shy [4]

Answer:

B

Step-by-step explanation:

The chances of the first student walking to school is 7/30.

Without replacement, there are 29 students left. Hence the chance of the second student walking to school is 6/29 of the original 7/30 chance.

(\frac{7}{30} )(\frac{6}{29} )=\frac{7}{145}

8 0
2 years ago
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Simplify. <br> 10/-4 - √3
Degger [83]

Answer:

here you go. hope this helps

5 0
2 years ago
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Put these decimals in order from least to greatest.<br> 8.009<br> 8.90<br> 8.09<br> 8.913
vagabundo [1.1K]

Answer:

8.009, 8.09, 8.90, 8.913

3 0
3 years ago
Solve this thing pls<br> <img src="https://tex.z-dn.net/?f=3%5Cleft%28q-7%5Cright%29%3D27" id="TexFormula1" title="3\left(q-7\ri
evablogger [386]

Answer:

  • Solution of equation ( q ) = <u>1</u><u>6</u>

Step-by-step explanation:

In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>

<u>Solution : -</u>

\quad \: \longmapsto \:  3(q - 7) = 27

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

\quad \: \longmapsto \:3q - 21 = 27

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

\quad \: \longmapsto \:3q -  \cancel{ 21} +  \cancel{21} = 27  +  21

On further calculations we get :

\quad \: \longmapsto \:3q = 48

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}}  =  \cancel {\frac{48}{3} }

On further calculations we get :

\quad \: \longmapsto \:   \pink{\boxed{\frak{q = 16}}}

  • <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are very our answer by substituting value of q in the given equation . So ,

  • 3 ( q - 7 ) = 27

  • 3 ( 16 - 7 ) = 27

  • 3 ( 9 ) = 27

  • 27 = 27

  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
3 0
2 years ago
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Find the length of UC on the attached diagram. Thank you!
ValentinkaMS [17]
<h2>Answer </h2>

The length of UC is 18

<h2>Explanation </h2>

First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.

We can infer from our picture that JN is 82 + 105, so JN = 187

We can also infer that JU = JH + HU

                                     JU = 22 + 96

                                     JU = 118

We can also infer that CN = 51

Now we can fin the length of UC:

UC=JN-(JU+CN)

UC=187-(118+51)

UC=18

We can conclude that the length of UC is 18.

3 0
3 years ago
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