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dalvyx [7]
2 years ago
15

*ੈ✩‧₊˚

Mathematics
1 answer:
grigory [225]2 years ago
3 0

Answer:8 1/4 cups

Step-by-step explanation:

All you must do is multiply 2.75 (which is 2 3/4 in decimal form) by 3 since Wendy is baking a TRIPLE recipe. So, the work will look like this: 2.75x3=8.25 or 8 1/4 cups of flour.

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Write a simplified polynomial expression in standard form to represent the area of the rectangle below.
JulijaS [17]
Given:
Rectangle shape.
One side: 5x + 2
other side: x - 4

Area = length * width
Area = (5x+2)(x-4)
A = 5x(x-4) +2(x-4)
A = 5x² - 20x + 2x - 8
A = 5x² - 18x - 8
6 0
3 years ago
Read 2 more answers
An experiment was conducted to observe the effect of an increase in temperature on the potency of an antibiotic. Three 1-ounce p
ludmilkaskok [199]

Answer:

a) y=-0.317 x +46.02

b) Figure attached

c) S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03

Step-by-step explanation:

We assume that th data is this one:

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

a) Find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324

\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900

And the slope would be:

m=-\frac{1900}{6000}=-0.317

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60

\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27

And we can find the intercept using this:

b=\bar y -m \bar x=27-(-0.317*60)=46.02

So the line would be given by:

y=-0.317 x +46.02

b) Plot the points and graph the line as a check on your calculations.

For this case we can use excel and we got the figure attached as the result.

c) Calculate S^2

In oder to calculate S^2 we need to calculate the MSE, or the mean square error. And is given by this formula:

MSE=\frac{SSE}{df_{E}}

The degred of freedom for the error are given by:

df_{E}=n-2=12-2=10

We can calculate:

S_{y}=\sum_{i=1}^n y^2_i -\frac{(\sum_{i=1}^n y_i)^2}{n}=9540-\frac{324^2}{12}=792

And now we can calculate the sum of squares for the regression given by:

SSR=\frac{S^2_{xy}}{S_{xx}}=\frac{(-1900)^2}{6000}=601.67

We have that SST= SSR+SSE, and then SSE=SST-SSR= 792-601.67=190.33[/tex]

So then :

S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03

5 0
3 years ago
Put these in order starting from the smallest<br> 6^2 3^4 2^9<br> 5^3
Levart [38]

Answer:

6^2, 3^4, 5^3, and 2^9

Step-by-step explanation:

6^2= 36

3^4= 81

5^3= 125

2^9= 512

4 0
3 years ago
What is the base for the expression -6 to the power of 4
natima [27]

For this case we have that by definition it is fulfilled:

a ^ b

Where:

a: It is the base

b: It is the exponent

So, if we have the following expression:

-6 to the power of 4, is equivalent to: (-6) ^ 4

So we have to:

-6: It is the base

4: It is the exponent

Answer:

-6: It is the base

4: It is the exponent

8 0
3 years ago
Suppose f '' is continuous on (−[infinity], [infinity])
Angelina_Jolie [31]

Answer with Step-by-step explanation:

We are given that a function f(x) is continuous on (-\infty,\infty).

1.f'(-1)=0 and f''(-1)=-7

We have to find information about f.

When f'(-1)=0 and f''(-1)=-7 < 0

Then, function is maximum at x=-1.

Therefore, at x=-1, f has local maximum.

Answer:a)at x=-1 ,f has local maximum.

2.) if f'(4)=0 and f''(4)=0

We know that when f''(x)=0 then test fails  then the function has not maximum or minimum.

Therefore, at x=4 , f has not a maximum or minimum.

Answer:c) at x=4, f has not a maximum or minimum.

4 0
3 years ago
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