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3 years ago

Prove that

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = $\frac{1}{cosx}$ , cosecx = $\frac{1}{sinx}$

cotx = $\frac{cosx}{sinx}$ , tanx = $\frac{sinx}{cosx}$

Consider the left side

secA cosecA - cotA

= $\frac{1}{cosA}$ × $\frac{1}{sinA}$ - $\frac{cosA}{sinA}$

= $\frac{1}{cosAsinA}$ - $\frac{cosA}{sinA}$

= $\frac{1-cos^2A}{cosAsinA}$

= $\frac{sin^2A}{cosAsinA}$ ( cancel sinA on numerator/ denominator )

= $\frac{sinA}{cosA}$

= tanA = right side ⇒ proven

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Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le

Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes =68

$Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}$

$68= \frac{\text{Sum of all lengths}}{7}$

$68 \times 7 =\text{a+b+c+d+e+f+g}$

$476=\text{a+b+c+d+e+f+g}$ --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

$476=x+x+x+84+84+84+4x+14$

$476=7x+266$

$\frac{476-266}{7}=x$

$30=x$

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0

3 years ago

What is the length of the dotted line in the diagram below? Leave your answer in simplest radical form.

Pachacha [2.7K]

Answer:

$\sqrt{93}$

Step-by-step explanation:

8^2+5^2=c^2

64+25=c^2

89=c^2

c= $\sqrt{89}$ <-- this is the length of the rectangle at the bottom

2^2+( $\sqrt{89}$ )^2=c^2

4+89=c^2

c= $\sqrt{93}$ <-- length of dotted line (diagonal)

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2 years ago

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Prove that the figure is a parallelogram. If so, classify the parallelogram. Be specific and justify your answer.

sesenic [268]

Answer:

Step-by-step explanation:

If it is a parallelogram the opposite sides will a have the same slope.

Using the diagram we see from the coordinates of A and B:

Slope of AB = (5 - -1)/(-1 - -5)

= 6/4

= 3/2.

In the same way

slope of CD = (2 - -4) / (1 - -3)

= 3/2.

So AB and CD can be shown to be parallel.

Similarly the lines BC and AD are parallel.

So the figure is a parallelogram

Finding the perimeter (counting the units between the points):

Perimeter = 2AB + 2BC

By Pythagoras:

AB = sqrt (6^2 + 4^2) = sqrt 52

BC = sqrt (3^2 + 2^2) = sqrt 13

So Perimeter = 2sqrt52 + 2sqrt13

= 4sqrt13 + 2 sqrt13

= 6sqrt13

or 21.63 unit^2 to 2 decimal places.

Area = sqrt52 * perpendicular distance between the lines AB and CD.

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stepan [7]

Step-by-step explanation:

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Step-by-step explanation:

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