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Aleksandr-060686 [28]
3 years ago
7

[-16 (-0.2)]-[(-4)×0.66]

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

[-16(-0.2)] - [(-4)*0.66]

3.2 - (-2.64)

3.2+2.64 = 5.84

So, your answer is 5.84

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What is the approximate length of a pendulum that takes 2.4 pi seconds to swing back and forth?
sertanlavr [38]

Answer:

The approximate length of the pendulum is 46.08 ft

Step-by-step explanation:

The time (t) of pendulum oscillation is given as;

t = 2 \pi\sqrt{\frac{L}{g} }

where;

L is the length of the pendulum

g is acceleration due to gravity = 9.8 m/s² = 32.15 ft/s²

t is the time given as 2.4 π seconds

From the equation above, make L the subject of the formula;

t = 2 \pi\sqrt{\frac{L}{g} } \\\\\frac{t}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{t}{2\pi} )^2 =\frac{L}{g}  \\\\L = g*(\frac{t}{2\pi} )^2\\\\L = 32.15*(\frac{2.4 \pi}{2\pi} )^2\\\\L = 32.15 *1.44\\\\L = 46.296 \ ft

Therefore, the approximate length of the pendulum is 46.29 ft

The closest option is 46.08 ft

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The train travelled x + 200 km

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156

Step-by-step explanation:

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