Answer:
Tenth
Step-by-step explanation:
4- Tens
2- Ones
9- Tenths
7= Hundredth
X=5
Y=1
2x+4(2x-11)=6
+44 both sides
2x+8x=50
10x=50
Divide by 10 both sides
X=5
Plug in 5 to x and you will find y
Well, negatives are less than zero, and the greater the number the less it is, or in this case colder, so we know that the first two are -19, and -10, then comes 0, and increases from there. So, the answer would be B. (-19, -10, 0, 15, 28)
Did this help?
Answer:
-4, 0, 3, 5
Step-by-step explanation:
The number line is being counted by ones. So when it's complete, it would be like this:
-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
Hope this helps!!
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
