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Papessa [141]
3 years ago
8

Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit

h eight discussion sections would like to test if student performance differs by discussion section, where each discussion section has a different teaching assistant. The summary table below shows the average final exam score for each discussion section as well as the standard deviation of scores and the number of students in each section.
Sec 1 Sec 2 Sec 3 Sec 4 Sec 5 Sec 6 Sec 7 Sec 8
ni 33 19 10 29 33 10 32 31
Xi 92.94 91.11 91.8 92.45 89.3 88.3 90.12 93.35
si 4.21 5.58 3.43 5.92 9.32 7.27 6.93 4.57


The ANOVA output below can be used to test for differences between the average scores from the different discussion sections.


Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87
Residuals 189 7584.11 40.13


Conduct a hypothesis test to determine if these data provide convincing evidence that the average score varies across some (or all) groups. Check conditions and describe any assumptions you must make to proceed with the test.
Mathematics
1 answer:
adell [148]3 years ago
3 0

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

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aleksklad [387]

Answer:

4.12 kg

Step-by-step explanation:

Regular cakes:

1 dozen normal sponge cakes: 264 g plain flour

Vegetarian cakes:

1 dozen cakes: 264 g plain flour

4 eggs are replaced by 4 * 30 g of flour = 120 g flour

total flour for 1 dozen vegetarian cakes = 264 g + 120 g = 384 g

Proportion for regular cakes:

12 cakes to 264 g flour = 100 cakes to x grams flour

12/264 = 100/x

12x = 26400

x = 2200

2200 g flour for 100 regular cakes

Proportion for vegetarian cakes:

12 cakes to 384 g flour = 60 cakes to y grams flour

12/384 = 60/y

12y = 384 * 60

12y = 23040

y = 1920

1920 g flour for 60 vegetarian cakes

Total flour needed:

2200 g + 1920 g = 4120 g

4120 g * 1 kg/(1000 g) = 4.12 kg

Answer: 4.12 kg

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3 years ago
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yulyashka [42]

Answer:

-3

Step-by-step explanation:

H = -3

J = -1

J = -1

M=2

(-3+-1)+(-1+2)=-3

3 0
2 years ago
Read 2 more answers
Help with this question, please!
labwork [276]

Answer:

Y Intercept: 0, 2.5

X Intercept: 3.5, 0

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Also when writing coordinates, the x coordinate comes before the y one.

Hope this helps :)

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