Answer:
h[j(3)] = -20
Step-by-step explanation:
We need h(j(3)). First find j(3)
j(x) = -x, so
j(3) = -(3) = -3
Now find h(-3)
h(x) = 4x - 8, so
h(-3) = 4(-3) - 8
h(-3) = -12 - 8 = -20
So h[j(3)] = -20
1)1, 3, 5, 15, 23, 69, 115, 345
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I'm not completely sure but I think it is -5x.