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3 years ago

Someone help, geometry is so hard

Mathematics

1 answer:

elena55 [62]3 years ago

8 0

Answer:

61 degrees

Step-by-step explanation:

This is a 90 degree angle, and if you add 14 + 15, you get 29, so if you subtract 90-29, you get 61.

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Hannah has 127 books in her collection. Her school is hosting a book donation. There are z students at her school, and they each

erastova [34]

Then answer would be 300÷127=Z

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3 years ago

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Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3

s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $\frac{((a^2)^{-2})^5}{a^4.a^3}$

We know that when the bases are same the powers can be added. i.,e.,

(xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $\frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7}$

$\implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27}$

Also, $\frac{x^a}{x^b} = x^{a - b}$

This is nothing but, $\frac{1}{a^{27}}$ .

Note that $a$ cannot be zero here. The condition is provided in the question as well.

7 0

3 years ago

Write the equation in slope-intercept form of the line that passes through the points (-3, -10) and (5, 14)

hjlf

Answer:

-10, -3, 5, 14

Am not sure if this is correct

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3 years ago

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A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates

son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector $=\frac{\theta}{360}X\pi R^2$

Area of the smaller sector $=\frac{\theta}{360}X\pi r^2$

Area of shaded part =Area of the larger sector-Area of the smaller sector

$=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)$

From the diagram, R=10 Inch, r=10-7=3 Inch, $\theta=95^\circ$

Therefore, Area of the sector cleaned

$=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches$

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3 years ago

The value of sin^2 30° - cos^2 30° is

natulia [17]

Answer:

-1/2

Step-by-step explanation:

Im not going to go into detail about how to compute sin30 and cos 30, but know that sine and cosine are just the ratios between the sides of a 30-60-90 triangle with a hypothenuse of 1.

With that being said:

sin^2 30 - cos^2 30

= (1/2)^2 - ((sqrt3)/2)^2

= 1/4 - 3/4

= -1/2

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3 years ago

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