Answer:
if we take ratio then answer is option D
Answer:
Step-by-step explanation:
The hypothesis is written as follows
For the null hypothesis,
µd ≤ 10
For the alternative hypothesis,
µ > 10
This is a right tailed test
Since no population standard deviation is given, the distribution is a student's t.
Since n = 97
Degrees of freedom, df = n - 1 = 97 - 1 = 96
t = (x - µ)/(s/√n)
Where
x = sample mean = 8.9
µ = population mean = 10
s = samples standard deviation = 3.6
t = (8.9 - 10)/(3.6/√97) = - 3
We would determine the p value using the t test calculator. It becomes
p = 0.00172
Since alpha, 0.01 > than the p value, 0.00172, then we would reject the null hypothesis. Therefore, At a 1% level of significance, there is enough evidence that the data do not support the vendor’s claim.
<h3>
Answer:</h3>
- 6 large prints
- 12 small prints
<h3>
Step-by-step explanation:</h3>
<em>Numerical Reasoning</em>
Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...
... 2×$20 +45 = $85
To have revenue of at least $510, the studio must sell ...
... $510/$85 = 6
sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.
_____
<em>With an equation</em>
Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...
... 20·2x +45·x ≥ 510
... 85x ≥ 510
... x ≥ 510/85
... x ≥ 6
The studio needs to sell at least 6 large prints and 12 small prints.
Answer
My answer is in the photo above