All categories

3 years ago

How many 5-cent stamps are there in a half dozen?

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

6 0

Answer:

because a dozen is 12 and a half dozen is 6.

You might be interested in

Need help plz im big dum dum -_-

melamori03 [73]

Answer:

603

Step-by-step explanation:

First divide to get unit rate:

737/11= 67

Then multiply:

67*9= 603

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

A boat traveling at a constant rate. In 4 seconds, the boat travels 80 feet what is the rate the boat is traveling at in feel pe

Varvara68 [4.7K]

Answer: 20 feet per second

Step-by-step explanation:

Do 80 divided by 4

6 0

3 years ago

27 + (8-5) -am looking for the answer of number 7

Rasek [7]

Answer:

The answer to the equation from question 7 is 14.

Step-by-step explanation:

In question 7, we are given an equation.

2³ + (8 - 5)² - 3

First, subtract 5 from 8 in the parentheses.

2³ + 3² - 3

Next, solve the exponents for 2³ and 3².

8 + 9 - 3

Add 8 to 9.

17 - 3

Subtract 3 from 17.

So, the answer to this equation from question 7 is 14.

4 0

3 years ago

Who can help me PLEASE Instruction find the measure of the missing angles in the kite

mojhsa [17]

Both the angles will be 105°

Just add up the given angles, subtract the result by 360, and divide by 2.

8 0

3 years ago

the letters of the word independent are written on individual card and the cards are put into a box a card is selected and then

puteri [66]

Answer:

The probability of obtaining the letter p twice is 1/121

Step-by-step explanation:

Probability of Recurring Events

There are 11 letters in the word 'independent', one of which is the letter 'p'.

When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.

This means the individual probability of getting a 'p' is:

$\displaystyle P_1=\frac{1}{11}$

The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:

$\displaystyle P_2=\frac{1}{11}$

We'll use the multiplication rule. Just multiply the probability of the first event by the second.

$\displaystyle P=P_1*P_2=\frac{1}{11}*\frac{1}{11}$

$\displaystyle P=\frac{1}{121}$

The probability of obtaining the letter p twice is 1/121

6 0

2 years ago