Answer:
it's 10.00 because I used a calculator
If you multiply everything by 6, you can get rid of all of the fractions and it’ll be much easier to solve!
Answer:
A. H0: p = 0.67; H1: p < 0.67
A. The standard normal, since np > 5 and nq > 5.;
Test statistic = - 0.397 ;
Pvalue = 0.3457;
D. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
B. There is insufficient evidence at the 0.05 level to conclude that the true proportion of women athletes who graduate is less than 0.67.
Step-by-step explanation:
p = 0.67 ; q = 1 - p = 1 - 0.67
Sample size, n = 36
x = 23
Test for normality :
(36*0.67) = 24.12
(36 * (1-0.67)) = 11.88
For a normal distribution :
np ≥ 5 and n(1 - p) ≥ 5
The hypothesis :
H0 : p = 0.67
H1 : p < 0.67
The Test statistic :
Z = (phat - p) / √[(p(1 -p))/n]
Phat = x / n = 23 / 36
Z = ((24/36) - 0.67)) / √[(0.67(1 -0.67))/36]
Z = - 0.031 / 0.0783687
Z = - 0.396983
Z = - 0.397
Usong the Pvalue from Z calculator ;
Pvalue of Z = 0.3457
If Pvalue < α ; Reject H0 ; If otherwise, Fail to reject H0
Answer:
x-intercept: (-40,0)
y-intercept: (0,15)
Step-by-step explanation:
the x-intercept is the point that lies on the x-axis,
and the y-intercept is the point that lies on the y-axis.