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3 years ago

How do you solve 4(6x-1)=120 if you're solving for x

1 answer:

7 0

4(6x-1)=120
Multiply the number outside the parenthesis(4) with the numbers inside the parenthesis(6 and -1)
24x-4=120
Add 4 to both sides
24x=124
Divide both sides by 24
Final Answer: x= 5.1667 or 5 1667/10,000

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A 10 ounce container if milk contains 200 calories. how many calories does each ounce of milk contain?

kaheart [24]

The answer that is correct is 20 so there you go

5 0

4 years ago

PLEASE help me if you know the answer!! :)

Gennadij [26K]

360/9= 40
180-40= 140
140/2= 70

X=70

4 0

4 years ago

4×62=(4×n)+(4×2) how do I solve the problem?

Lera25 [3.4K]

Equation:

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3 years ago

A simple random sample of size nequals=8181 is obtained from a population with mu equals 77μ=77 and sigma equals 27σ=27. (a) De

ivanzaharov [21]

Answer:

a) $P(\bar X>81.5)=1-0.933=0.067$

b) $P(\bar X$

c) $P(73.4$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=77,\sigma=27)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

On this case $\bar X \sim N(77,\frac{27}{\sqrt{81}})$

Part a

We want this probability:

$P(\bar X>81.5)=1-P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >81.5)=1-P(Z$

$P(\bar X>81.5)=1-0.933=0.067$

Part b

We want this probability:

$P(\bar X\leq 69.5)$

If we apply the formula for the z score to our probability we got this:

$P(\bar X \leq 69.5)=P(Z\leq \frac{69.5-77}{\frac{27}{\sqrt{81}}})=P(Z$

$P(\bar X\leq 69.5)=0.0062$

Part c

We are interested on this probability

$P(73.4$

If we apply the Z score formula to our probability we got this:

$P(73.4$

$=P(\frac{73.4-77}{\frac{27}{\sqrt{81}}}$

And we can find this probability on this way:

$P(-1.2$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1.2$

3 0

4 years ago

What's 0.81 written as a fraction

Tasya [4]

∙•❁If you want to turn .81 to a fraction take out the decimal and then write $\frac{81}{100}$ and there is your fraction! Your answer shall be $\frac{81}{100}$ ❁•∙

∙•❁I hope this helps!❁•∙

4 0

3 years ago

Read 2 more answers