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Shtirlitz [24]
2 years ago
6

Many 4 digit numbers can be formed using only the numbers 3 2 7 6 0 4 9 if

Mathematics
1 answer:
ryzh [129]2 years ago
6 0
Hi!

The combination of 4 digit numbers using those numbers are: 3, 276; 3, 762; 3, 267; 3, 726; 3, 672 etc. This is pretty easy, now you try.

Hope I helped! Have a nice day!
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Word problem plz help thanks fam 7.04​
givi [52]

g/2 + 4

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3 years ago
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Use the given equation to determine if the points in the brackets are on the graph
dmitriy555 [2]

The points in the brackets are on the graph are (0, 2) and (6, 10)

<h3>How to determine if the points in the brackets are on the graph?</h3>

The equation of the line is given as

4x - 3y = -6

The points are given as:

{(0,2),(1,3),(4,7),(6,10)}

Rewrite as

(x, y) = {(0,2),(1,3),(4,7),(6,10)}

Next, we substitute the x and y values in the equation 4x - 3y = -6

So, we have

(0, 2):

4(0) - 3(2) = -6

-6 = -6 ---- true

(1, 3):

4(1) - 3(3) = -6

-5 = -6 ---- false

(4, 7):

4(4) - 3(7) = -6

-5 = -6 ---- false

(6, 10):

4(6) - 3(10) = -6

-6 = -6 ---- true

Hence, the points in the brackets are on the graph are (0, 2) and (6, 10)

Read more about linear equations at:

brainly.com/question/2226590

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3 0
1 year ago
Helpp plzzz I will mark brainliestttt
miskamm [114]

Answer:

it 152.3

Step-by-step explanation:

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2 years ago
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a school had 690 students sign up for the trivia teams if they wanted to have nine teams with the same number of students on eac
Anna11 [10]

Answer:

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Step-by-step explanation:

690 + 30 = 720

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8 0
3 years ago
A jogger goes 1.5km west and then turns south.If the jogger finishes 1.7 km from the starting point,how far south did the jogger
kakasveta [241]
Hello!

You can use the Pythagorean Theorem to solve this

a^{2} + b^{2} = c^{2}

c is the hypotenuse
a and b are the legs

Put in the values you know

1.5^{2} + b^{2} = 1.7^{2}

Square the numbers

2.25+ b^{2} =2.89

Subtract 2.25 from both sides

b^{2} =0.64

Take the square root of both sides

b = 0.8

The answer is 0.8km

Hope this helps!
6 0
3 years ago
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