A is a constant. Find A such that the equation 2x + 1 = 2A + 3(x + A) has a solution at x = 2.

1 answer:

4 0

   2x + 1 = 2A + 3(x + A)

You want x=2 to be a solution.
So the equation will be a true statement when

   2(2) + 1 = 2A + 3(2 + A)

   4 + 1 = 2A + 6 + 3A

Combine like terms: 5 = 5A + 6

Subtract 6 from each side: -1 = 5A

Divide each side by 5: <em> -0.2 = A</em>

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