Answer:
Step-by-step explanation:
b=bench
852=b+(b-98) since the table is less than the bench by 98$
852-b=b-98
950-b=b
950=2b
475=b
C=7•2=14 this should be right idk
Answer:
Perimeter = 15
Step-by-step explanation:
We are told that the length of each of the 3 sides of the triangle are consecutive odd integers.
Thus means that we can write the 3 terms as;
(x - 2), x, (x + 2)
Thus, perimeter is;
P = (x - 2) + x + (x + 2)
P = 3x
If an angle is 120°, it means that the corresponding side that is directly opposite the angle is the largest side of the triangle.
Thus, this side is (x + 2)
Using cosine rule, we have;
(x + 2)² = x² + (x - 2)² - 2(x(x - 2))cos 120
Expanding, we have;
x² + 4x + 4 = x² + x² - 4x + 4 - (2x² + 4x)(-½)
This reduces to;
4x = x² - 4x + x² - 2x
2x² = 10x
2x = 10
x = 10/2
x = 5
Thus, other sides are;
(x - 2) = 5 - 2 = 3
And (x + 2) = 5 + 2 = 7
So,perimeter is;
P = 3x = 3 × 5 = 15
Answer:
Width
Step-by-step explanation:
When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:
Single value grouping where each class has one distinct value.
In Cutpoint grouping is used when the observations have decimal points
In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.
Your answer for Q is rotated over the period and flipped upside down.
