The target cost for Model J20 is $2000.
The required cost reduction is $30.
The total saving will be $30.3.
<h3>How to compute the cost?</h3>
The target cost will be:
= Sales price - (100% × Target cost)
= 400 - (100% × Y)
Y + Y = 400
2Y = 400
Y = 400/2 = 200
Target cost = $200
Therefore, the target cost is $200.
The required cost reduction will be:
= $230 - $200
= $30
The required cost reduction is $30.
The three engineering improvements together will be:
Direct labor reduction = 7.5
Additional inspection = 17
Injection molding = 5.8
Total savings = 30.3
The total savings is $30.3.
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False
A cubic foot would be 12 x 12 x 12 = 1728 cubic inches
r = ![\frac{3t}{t - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B3t%7D%7Bt%20-%201%7D)
multiply both sides of the equation by r - 3
t(r - 3 ) = r ( distribute and collect terms in r together )
tr - 3t = r
tr - r = 3t ( factor out r )
r(t - 1 ) = 3t ( divide both sides by r - 1 )
r = ![\frac{3t}{t - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B3t%7D%7Bt%20-%201%7D)
Answer:
your answer to that is D hope that helps
Answer:
R: (16, 2)
Step-by-step explanation:
Let (x, y) be the point R
(x - 10)/2 = 3 and (y + 12)/2 = 7
x - 10 = 6 y + 12 = 14
x = 16 y = 2
R: (16, 2)