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3 years ago

7

the student government association is selling roses for valentines day to raise money for their trip to the state convention. Th

e cost of each rose is $$2.50 and the florist charges a delivery fee of $50. The class plans to sell the roses for $7.00 each.

2 answers:

Maslowich3 years ago

6 0

the questions are A; Define the variable B; Write a cost function C; Write a revenue function D; Write a profit function

Mariulka [41]3 years ago

5 0

Is that a question? and are there any answers to go with it if so?

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Please help me on this!

Blizzard [7]

1,2, and 6 are all no’s but everything else is yes I believe

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2 years ago

Case 1: Jackson is a recent college graduate who just got his first job. He commutes approximately 35 minutes each way to his ne

Vikentia [17]

The financially responsible choice would be for Jackson to lease a car for right now. as Jackson moves up in the company to a high paying position he should pay off the car. this way Jackson isn’t in any debt while he’s making his modest income and not have any money left.

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2 years ago

What is the answer to the qustion 0.3h+1.2=0.1h-2.6

andreev551 [17]

Answer:

-19

Step-by-step explanation:

0.3h+1.2=0.1h-2.6

.2h+1.2=-2.6

.2h=-3.8

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7 0

3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

2 years ago

Anyone know how to do #21?

Andreas93 [3]

Would it be y2 ? idk im not sure but i tried

6 0

3 years ago