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3 years ago

Module 1 Exam

Mathematics

1 answer:

Anon25 [30]3 years ago

5 0

Answer: 50

Step-by-step explanation:

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I have the answer I just have this one question. Will all the paint fit into the bucket?

klasskru [66]

Answer:

brandon

Step-by-step explanation:

Initially, there id 4 pints of green paint in the bucket.

As the green paint is made from equal amounts of yellow paint and blue paint, so, the initial amount of yellow and blue paint in the bucket is 2 pint each.

Let x pints of yellow paint to be added to the bucket to make the desired shade.

Total amount of the paint in the bucket, after addition of pints of yellow color become pint, in which the ampunt of yellow color is pints.

As, the ampunt of yellow color is 80% of the total amount of the mixture, so

So, 6 pints of yellow paint to be added to the bucket to make the desired shade.

Hence, Brandon is correct.

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2 years ago

What is the slope of the line parallel to the line Y equals - 3X -8

Georgia [21]

Answer:

-3 is the slope.

Step-by-step explanation:

8 0

3 years ago

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Guys please HELP ASAP!!!!!!!

balandron [24]

R(9,0)
S(8,-4)
T(7,4)
V(6,0)

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3 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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3 years ago

If LM = 6, what is the perimeter of △PKQ?

Tanya [424]

16 i believe
ur welcome

7 0

3 years ago

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