If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
I don't understand the question
Answer:
217 kg
Step-by-step explanation:
i just know the answer
There are 3 coefficents. There is one in 6a, which is 6, one in 8z, which is 8, and one in 1/2n, which is 1/2.
Hope this helps, Ngam123!
