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ki77a [65]
4 years ago
14

You have 90 oz of egg noodles. You need 5 oz to make one serving of chicken noodle soup. How many servings can you make?

Mathematics
2 answers:
kap26 [50]4 years ago
8 0

Answer: 450 oz

Step-by-step explanation: multiply

Julli [10]4 years ago
7 0

Answer:

You can make 18 servings.

Step-by-step explanation:

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Give the solution set for the inequality<br> 7x &lt; 7(x - 2) in interval notation.
eduard

<u>ANSWER:</u>

The solution set for the inequality 7x < 7(x - 2) is null set \varnothing

<u>SOLUTION:</u>

Given, inequality expression is 7x < 7 × (x – 2)

We have to give the solution set for above inequality expression in the interval notation form.

Now, let us solve the inequality expression for x.

Then, 7x < 7 × (x – 2)

7x < 7 × x – 2 × 7

7x < 7x – 14

7x – (7x – 14) < 0

7x – 7x + 14 < 0

0 + 14 < 0

14 < 0  

Which is false, so there exists no solution for x which can satisfy the given equation.

So, the interval solution for given inequality will be null set

Hence, the solution set is \varnothing

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Step-by-step explanation:

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Factor each.<br><br><br> Please help!
Naddika [18.5K]

Answer:

1) The factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) The factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0

So, factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0

So, factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

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3 years ago
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