Answer:
There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.
Step-by-step explanation:
We are given the following in the question:
Group 1:

Group 2:

Alpha, α = 0.05
First, we design the null and the alternate hypothesis
Since, the population variances are equal and that the two populations are normally distributed, we use t-test(pooled test) for difference of two means.
Formula:
Pooled standard deviation



Putting all the values we get:



Now,

Since,

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.
We conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2.
There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.
Step-by-step explanation:
1.5 : 2.5
= 1.5/2.5
15/25
3/5
the ratio is 3 : 5
5 shapes are dots because ADD on Morse code is •- -•• -••
Answer:
1) The terminal side lies in quadrant 2
2) cosФ = -15/17
3) tanФ = -8/15
Step-by-step explanation:
1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1
2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17
3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15