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kondaur [170]
3 years ago
11

Give the solution set for the inequality 7x < 7(x - 2) in interval notation.

Mathematics
1 answer:
eduard3 years ago
3 0

<u>ANSWER:</u>

The solution set for the inequality 7x < 7(x - 2) is null set \varnothing

<u>SOLUTION:</u>

Given, inequality expression is 7x < 7 × (x – 2)

We have to give the solution set for above inequality expression in the interval notation form.

Now, let us solve the inequality expression for x.

Then, 7x < 7 × (x – 2)

7x < 7 × x – 2 × 7

7x < 7x – 14

7x – (7x – 14) < 0

7x – 7x + 14 < 0

0 + 14 < 0

14 < 0  

Which is false, so there exists no solution for x which can satisfy the given equation.

So, the interval solution for given inequality will be null set

Hence, the solution set is \varnothing

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Step-by-step explanation:

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Hope it helps!

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Aubrey claims that if the dimensions of the parallelogram shown are doubled, then the area of the larger parallelogram will be 4
Ostrovityanka [42]

Answer:

Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.

Step-by-step explanation:

A parallelogram with a base of 6 inches and height of 3 inches. A side has a length of 5 inches.

Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.

Aubrey is correct because the area of the new parallelogram is 10 (7) = 70 square inches. The original area is 18 square inches. Since 4 (18) = 72, it is about 4 times larger than the original.

Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 18 square inches so the new parallelogram will have an area of 2 (18) = 36, or two times more than the original.

Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 30 square inches so the new parallelogram will have an area of 2 (30) = 60, or 2 times more than the original.

Workings

Area of a parallelogram=base×height

Original parallelogram

Base=6 inches

Height=3 inches

Area=base×height

=6×3

=18 square inches

New parallelogram with doubled dimensions

Base=6 inches doubled=12 inches

Height=3 inches doubled=6 inches

Area=base×height

=12×6

=72 square inches

New area=4 times original area

New area=4×18

New area=72 square inches

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3 years ago
Please answer correctly !!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!
boyakko [2]

Answer:

49

Step-by-step explanation:

y = 7^2

= 49

5 0
3 years ago
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